提交记录 #249

提交时间：2024-11-17 20:59:58
语言：c 状态：Unaccepted
编译情况：编译成功 
code.c: In function ‘main’:
code.c:11:19: warning: format ‘%c’ expects argument of type ‘char *’, but argument 2 has type ‘int *’ [-Wformat=]
   11 |     while(scanf("%c",&a)!=EOF)
      |                  ~^  ~~
      |                   |  |
      |                   |  int *
      |                   char *
      |                  %lc
code.c:9:25: warning: unused variable ‘aa’ [-Wunused-variable]
    9 |     int a,i=1,j=0,l,zzi,aa;
      |                         ^~
固定测试点#1:
waWrong Answer
time 0.000s
memory 492 kB
固定测试点#2:
acAccepted
time 0.000s
memory 556 kB
固定测试点#3:
waWrong Answer
time 0.000s
memory 228 kB
固定测试点#4:
waWrong Answer
time 0.005s
memory 232 kB
附加测试点暂不可用
... 不可用
time N/A
memory N/A

sp0【千酱找的额外题】多项式导数计算 

#include<stdio.h>

char c[150000];
int b[10000],x[10000],f[10000];
int xs[10000],m[10000];
int main()
{
    int a,i=1,j=0,l,zzi,aa;
    scanf("f(x)%c",&c[0]);
    while(scanf("%c",&a)!=EOF)
    {
        j++;
        if(a=='\n')
        {
            c[j]='+';
            b[i]=j;
            break;
        }
        c[j]=a;
        if(a=='+')
        {
            b[i]=j;
            i++;
        }
        if(a=='x') x[i]=j;
        if(a=='^') f[i]=j;
    }
    zzi=i;//多项式项数
    for(i=1;i<=zzi;i++)
    {
        if(x[i]==0&&f[i]==0)
        break;
        for(l=b[i-1]+1;l<x[i];l++)
        {
            xs[i]*=10;
            xs[i]+=c[l]-48;
        }
        if(xs[i]==0)
        xs[i]=1;
        if(f[i]!=0)
        {
            for(l=f[i]+1;l<b[i];l++)
            {
                m[i]*=10;
                m[i]+=c[l]-48;
            }
            if(m[i]==0)
            m[i]=1;
        }
    }
    for(i=1;i<=zzi;i++)
    {
        if(xs[i]!=0&&m[i]!=0)
        {
            xs[i]*=m[i];
            m[i]-=1;
        }
    }
    printf("f'(x)=");
    if(x[1]==0)
    printf("0");
    else
    {
        for(i=1;i<=zzi;i++)
        {
            if(i!=1&&xs[i]!=0)
            printf("+");
            if(xs[i]>1&&m[i]>1)
                printf("%dx^%d",xs[i],m[i]);
            else if(xs[i]==1&&m[i]>1)
                printf("x^%d",m[i]);
            else if(xs[i]>1&&m[i]==1)
                printf("%dx",xs[i]);
            else if(xs[i]==1&&m[i]==1)
                printf("x");
            else if(xs[i]>1&&m[i]==0)
                printf("%d",xs[i]);
            else if(xs[i]==1&&m[i]==0)
                printf("1");
        }
    }
    printf("\n");
}
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