提交记录 #330

编译情况：编译成功

code.c: In function ‘main’:
code.c:16:23: warning: assignment to ‘char’ from ‘void *’ makes integer from pointer without a cast [-Wint-conversion]
   16 |             *(index+r)=NULL;
      |                       ^

固定测试点#1:

Accepted

0.000s

232 kB

固定测试点#2:

Accepted

0.000s

228 kB

固定测试点#3:

Accepted

0.000s

228 kB

额外测试点#1:

Wrong Answer

0.001s

496 kB

52【字符】字符替换*——用指针更方便

#include <stdio.h>  
#include <stdlib.h>  
#include <string.h>  
#include <ctype.h>
int main(){
    char *p = malloc(sizeof(char) * 200 );
    char *index = malloc(sizeof(char) * 20 );
    char *excg = malloc(sizeof(char) * 20 );
    int i, j=0;
    fgets(p, 200, stdin);
    fgets(index, 20, stdin);
    int r=0;
    while(r<=20){
        if(*(index+r)=='\n'){
            *(index+r)=NULL;
            break;
        }
        else{
            r++;
        }
    }
    fgets(excg, 20, stdin);
    for(i=0; *(p+i) != '\n'; i++){
        if( (p+i)==strstr(p, index)){
            for(int q=0; *(excg+q) != '\n'; q++){
                putchar(*(excg+q));
            }
            while(*(p+i)==*(index+j)){
                i++, j++;
            }
            i--;
        }
        else{
            putchar(*(p+i));
        }
    }    
    printf("\n");
    return 0;
}