提交记录 #517

编译情况：编译成功

code.c: In function ‘main’:
code.c:65:10: warning: format ‘%s’ expects argument of type ‘char *’, but argument 2 has type ‘char (*)[100000]’ [-Wformat=]
   65 |  scanf("%s",&yuan);
      |         ~^  ~~~~~
      |          |  |
      |          |  char (*)[100000]
      |          char *

固定测试点#1:

Accepted

0.000s

292 kB

固定测试点#2:

Accepted

0.000s

292 kB

固定测试点#3:

Accepted

0.000s

288 kB

额外测试点#216:

Wrong Answer

0.000s

296 kB

H17【选做•同学出题】动手实现Base64算法

#include<stdio.h>   
#include<math.h>   
#include<string.h>   
char jiami[10000];   
char dic[65]={"ABCDEFGHIJKLMNOPQRSTUVWXYZabcdefghijklmnopqrstuvwxyz0123456789+/"};   
int erjinzhi[1000000]={0},p=0,jiamishu[100000];
void change(int num)   
{   
    int k=p+7;   
 while(k>=p)   
 {   
      erjinzhi[k]=num%2;   
     num/=2;   
        k--;   
   }   
  p+=8;   
}   
int chongpai(int g)   
{   
  while(g%3!=0)   
  {   
      p+=8;   
      g++;   
   }   
  while(p%6!=0)   
  {   
      p++;   
   }   
  int k=0,m=0,n=0;   
   while(k<p)   
  {   
      jiamishu[n]+=erjinzhi[k]*pow(2,5-m);   
       m++;   
       k++;   
       if(m==6)   
       {   
          m=0;   
           n++;   
       }   
  }   
  return n;   
}   
void Jiami(int n,int g)   
{   
  for(int i=0;i<n;i++)   
    {   
      jiami[i]=dic[jiamishu[i]];   
 }   
  for(int i=n-1;i>=n-g;i--)   
   {   
      if(jiami[i]=='A')   
      {   
          jiami[i]='=';   
      }   
      else       
       {   
          return;   
        }      
   }   
}   
int main()   
{   
   char yuan[100000];   
 scanf("%s",&yuan);   
 for(int i=0;i<strlen(yuan);i++)   
 {   
      int num=yuan[i];   
       change(num);   
   }   
  int g=strlen(yuan);   
    int n=chongpai(g);   
 Jiami(n,3-g%3);   
    printf("%s\n",jiami);   
  return 0;   
}